a = 2.2;
b = -1;
c = -1;
D = b^2 - 4*a*c;
x1 = (-b + sqrt(D))/(2*a)
x2 = (-b - sqrt(D))/(2*a)
i1 = 1/x1 - 1
i2 = 1/x2 - 1

X = [-100, -100, 220]
X(1)    % gets the number in position 1
X(2)
X(3)
X(end)
disp("The IRR is:")
irr(X)