clc
A = (9:-.5:-18)'
length(A)
numel(A)
size(A) % it gives you the number of rows and columns
A(10) = -3
B = [7 -1 3 5 8 exp(1)]
B1 = B'
C = exp(abs(B1 + 2)./B1.^2)
A.^(1/3) - 3